2b^2+32b+128=0

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Solution for 2b^2+32b+128=0 equation:


Simplifying
2b2 + 32b + 128 = 0

Reorder the terms:
128 + 32b + 2b2 = 0

Solving
128 + 32b + 2b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '2'.
2(64 + 16b + b2) = 0

Factor a trinomial.
2((8 + b)(8 + b)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(8 + b)' equal to zero and attempt to solve: Simplifying 8 + b = 0 Solving 8 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + b = 0 + -8 b = 0 + -8 Combine like terms: 0 + -8 = -8 b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(8 + b)' equal to zero and attempt to solve: Simplifying 8 + b = 0 Solving 8 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + b = 0 + -8 b = 0 + -8 Combine like terms: 0 + -8 = -8 b = -8 Simplifying b = -8

Solution

b = {-8, -8}

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